X^2-7+16x=0

Solution for X^2-7+16x=0 equation:

X^2-7+16X=0

a = 1; b = 16; c = -7;
Δ = b2-4ac
Δ = 162-4·1·(-7)
Δ = 284
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{284}=\sqrt{4*71}=\sqrt{4}*\sqrt{71}=2\sqrt{71}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{71}}{2*1}=\frac{-16-2\sqrt{71}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{71}}{2*1}=\frac{-16+2\sqrt{71}}{2}
$